Please review this video. It is 6 minutes and twenty-nine seconds in length It is found at.
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Use of an electromagnetic coil to heat water in a ferromagnetic (steel) pipe.
The pipe is one inch in diameter and just long enough to be surrounded by ten windings of electromagnetic copper coils. Please refer to video for description of electromagnetic coils.
Please advise the actual amperage needed to heat the water in an iron or steel pipe one inch in diameter and just long enough to be covered by 10 windings of copper coil to 250 degrees Fahrenheit.
Two millimeter copper wire was used. For the 250 degree Fahrenheit temperature I am seeking, do I need ten windings of the wire? How many amps would ten windings require? How many amps would three windings require? The one inch pipe is still to be long enough to be covered by ten windings of wire.
The video suggests that 12 volts (DC?) and three amps are enough to reach 166 degrees Celsius. Is this correct? Would there be enough heat energy to heat the water in the tube? Also, the video shows a solid section of iron. I am trying to heat a pipe containing water. Does this change the amperage required?
Please specify the diameter of the copper wire used in the coil. Would it be 2mm? Also, what is the outside diameter of the windings?
Is the iron tube heated by the near magnetic field or the far magnetic field? Is the white tube shown in the video necessary? What will be the diameter of the copper coil windings?
The water will change to a steam state. What happens to the steam is the subject of a different study.
The assignment is to determine the amperage needed to raise the temperature of the water to 250 degrees Fahrenheit starting in a fifty-degree Fahrenheit atmosphere.
The secondary part of this project is to determine the amperage needed to heat water in the same tube to 250 degrees Fahrenheit using instead a resistance heating wire inside the same tube. I need a comparison of the two methods.
Is the amperage the same whether the electric current is provided by a 12 volt DC battery or a 120 Volt AC 15 Ampere wall outlet as used in the USA with an inverter to create DC current?
Please provide copy of your calculations.
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