Dibatalkan

Javascript Expert Needed (Jquery/Sencha EXTjs/Appcelerator, etc.) for Creative Web App

I have a web app coded in CSS/HTML/JS/Jquery that requires daily updates. I am looking for someone available for 12-15 hours a week for interface/view updates, including JS/Jquery. PHP knowledge is a plus, but I have other programmers working on the backend of the app. This is a long-term project that will provide a set number of hours of programming for the ideal candidate. I will send more details and the site/server info to qualified candidates.

Kemahiran: Amazon Web Services, Javascript, Memasang Skrip, Skrip Kekerang

Lihat lagi: web app programming, programming javascript, c++ programming for expert, c++ programming expert needed, javascript for programmers, js jquery, jquery programming, javascript programmers, javascript expert, extjs, css html jquery, creative web, creative programming, Appcelerator, javascript expert needed, sencha extjs php, sencha project, javascript week, app jquery, extjs week

Tentang Majikan:
( 194 ulasan ) Missoula, United States

ID Projek: #2710904

14 pekerja bebas membida secara purata $7/jam untuk pekerjaan ini

jacobdd1

See private message.

$7.28 USD / jam
(88 Ulasan)
6.1
s4234

See private message.

$7.28 USD / jam
(64 Ulasan)
5.5
EnvisionTechs

See private message.

$7.28 USD / jam
(17 Ulasan)
4.4
syedi

See private message.

$7.28 USD / jam
(10 Ulasan)
4.2
ynhat

See private message.

$7.28 USD / jam
(40 Ulasan)
4.0
go4webin

See private message.

$7.28 USD / jam
(22 Ulasan)
3.8
ahmadrasheed

See private message.

$6.37 USD / jam
(7 Ulasan)
3.4
wesamgerges

See private message.

$6.37 USD / jam
(5 Ulasan)
2.7
skapsl

See private message.

$5.46 USD / jam
(5 Ulasan)
2.7
igentechnolabsvw

See private message.

$7.28 USD / jam
(3 Ulasan)
2.4
momentai

See private message.

$7.28 USD / jam
(0 Ulasan)
0.0
vw8121088vw

See private message.

$4.55 USD / jam
(1 Ulasan)
0.0
lxzero

See private message.

$6 USD / jam
(0 Ulasan)
0.0
raskinlove

See private message.

$7.28 USD / jam
(3 Ulasan)
0.5