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third times, which set of three

you see number 7 has three numbers attached to it on 2367 and number 7 has three numbers attached to it 1780, the remainder is 459. now if number 7 appears again which three number will be attached. my record shows A= 2367, B=1780, C=459 = 1780 in which we have three sets of A,B,C so two numbers of A, or B, Or C is attached with one lose so the answer is 1780 , in other words number 7 can be 2 of A, or two of B, or two of C with one is attached to with no reason. in this case 7+ B,18 and C, 4 . Your job is to determine how you come up with answer. two more example, 4159+ 6357, 028 remainder answer is 5164. on third example 1248 + 8760, remainder 359, answer is 8950

Kemahiran: Matlab and Mathematica

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