Add SELECT TAG to function with "Dynamic INPUT fields to auto submit all to mysql" jQuery

This is an easy 15 min. work to make little extra income for java jquery expert.

Below is a script for automatically submitting forms to a MySQL database, but it doesn't work for <select> tags. How can I make this script work for those as well?

I have been struggling to include values from

<SELECT id="group1" name="group1">has over 100 options</select>

<SELECT id="group2" name="group2">has over 100 options</select>

along with other input fields to autosubmit as following

//script start

<script type="text/javascript">

// JQUERY: Plugin "autoSumbit"

(function($) {

[url removed, login to view] = function(options) {

return [url removed, login to view](this, function() {

// VARIABLES: Input-specific

var input = jQuery(this);

var column = [url removed, login to view]('name');

// VARIABLES: Form-specific

var form = [url removed, login to view]('form');

var method = [url removed, login to view]('method');

var action = [url removed, login to view]('action');

// VARIABLES: Where to update in database

var where_val = [url removed, login to view]('#where').val();

var where_col = [url removed, login to view]('#where').attr('name');

// ONBLUR: Dynamic value send through Ajax

[url removed, login to view]('blur', function(event) {

// Get latest value

var value = [url removed, login to view]();

if ([url removed, login to view]('type') == "checkbox")


if ([url removed, login to view]('checked') ){

value = 1;


value = 0;



// AJAX: Send values

[url removed, login to view]({

url: action,

type: method,

data: {

val: value,

col: column,

w_col: where_col,

w_val: where_val


cache: false,

timeout: 10000,

success: function(data) {

// Alert if update failed

if (data) {



// Load output into a P

else {






// Prevent normal submission of form

return false;





// JQUERY: Run .autoSubmit() on all INPUT fields within form


jQuery('#ajax-form INPUT').autoSubmit();



<form id="ajax-form" class="autosubmit" method="POST" action="[url removed, login to view]">



<div><input name="date" value="'.$Row['date'].'" /></div>

<div><input name="job" value="'.$Row['job'].'" /></div>

<div><input name="numb" value="'.$Row['numb'].'" /></div>

<div><input name="ri_amount" value="'.number_format($Row['ri_amount']).'" /></div>

<div><input name="ri_code" value="'.$Row['ri_code'].'" />

<div id="ri_codemenu">

<select id="group1" name="group1">

<option value="112" '. ((in_array('112', $ricode_array)) ? 'selected' : '').'>value1</option>

<option value="113" '. ((in_array('113', $ricode_array)) ? 'selected' : '').'>value2</option>

<option value="114" '. ((in_array('114', $ricode_array)) ? 'selected' : '').'>value3</option>



<div class="payamount"><input name="shi_amount" value="'.number_format($Row['shi_amount']).'" /></div>

<div class="shicode"><input name="shi_code" value="'.$Row['shi_code'].'" />

<div id="shi_codemenu">

<select id="group2" name="group2">

<option value="112" '. ((in_array('112', $shicode_array)) ? 'selected' : '').'>value1</option>

<option value="113" '. ((in_array('113', $shicode_array)) ? 'selected' : '').'>value2</option>

<option value="114" '. ((in_array('114', $shicode_array)) ? 'selected' : '').'>value3</option>




<div class="paytax"><input name="tax" value="'.$Row['tax'].'" /></div>

<div id="donebox"><input id="done'.$bi.'" type="checkbox" name="done" value="'.$Row['done'].'" '. ((in_array('1', $done_array)) ? 'checked' : '').'/><!--<label for="done'.$bi.'"></label>-->


<input id="where" type="hidden" name="id" value="'.$Row['id'].'" />



// script end

//[url removed, login to view]

function clean($value){

return mysql_real_escape_string($value);



// FORM: Variables were posted

if (count($_POST)){

// Prepare form variables for database

foreach($_POST as $column => $value)

${$column} = clean($value);

// Perform MySQL UPDATE

$result = mysql_query("UPDATE accountant SET ".$col."='".$val."'

WHERE ".$w_col."='".$w_val."'")

or die ('Unable to update row.');


Kemahiran: AJAX, HTML, Javascript, jQuery / Prototaip, PHP

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Tentang Majikan:
( 11 ulasan ) Bunkyoku, Japan

ID Projek: #10115644

Dianugerahkan kepada:


Hi, I think I have solution for your problem. Try add this one line "jQuery("#ajax-form SELECT").autoSubmit();" on your code like on example below. // JQUERY: Run .autoSubmit() on all INPUT fields within form j Lagi

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Hello It can be fixed right now Let me know if you are interested. Thank you ============================================

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Hello, is this code a snippet taken from a php string? I wont be able to run it correctly on my localhost, the best would be to send me the whole files in a rar file or letting me access the files on your own server ot Lagi

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I have great experiences on this kind of [login to view URL] if have a chance to work with you on this project. I can work directly via Teamview. Best regards.

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Hello. Welcome to your proposal. I am a MySQL, PHP, Javascript expert. I completed the many web development projects in the past and I have a lot of experience in them.= I assure high quality about your task. Thank Lagi

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Hi sir Thank you for your post. I am really interested to work in your project. I have 10 years experience in web development. I have gained enough experiences in web design, javascript, PHP and MYSQL. High Qualit Lagi

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