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VICIDIAL Asterisk Pass CLID to Agent Softphone

8 freelancers are bidding on average $129 for this job

iKcon

Hello. We have reviewed your requirements and will complete all. Relevant Skills and Experience We have been dealing with Vicidial, GoAutodial and many more products from past 7 years. Proposed Milestones $133 USD - Lagi

$133 USD dalam 3 hari
(13 Ulasan)
4.9
aiplwriter

Im Sourish, I'm an asterisk, vicidial and linux expert. Im a vicidial consultant and have installed 30+ vicidial servers in last 2 years. I think I can complete the required configurations. Relevant Skills and Experie Lagi

$111 USD dalam 3 hari
(19 Ulasan)
4.3
manindermarok

As per understanding from your brief description, I think I can easily make your wish done with my skills level contact me once and I guarantee it that you will get the perfect solution for your need. Relevant Skills Lagi

$155 USD dalam 3 hari
(19 Ulasan)
4.1
fameal

Hi! Facundo here. I believe that you need the agent to receive each call. I can manage to make Vicidial make the softphoe ring each call and also show the agent the information on screen. Relevant Skills and Experienc Lagi

$160 USD dalam 2 hari
(6 Ulasan)
3.7
APCTelco

I have 9 years of hands on experience in installation

$133 USD dalam 3 hari
(4 Ulasan)
3.1
niku28

i can help you resolve this with your vicidial. but need more information regarding this issue Relevant Skills and Experience vicidial, centOS Proposed Milestones $111 USD - Vicidial config what is the CLID your age Lagi

$111 USD dalam sehari
(1 Ulasan)
2.2
MetaoriginLab

We are a Team of Technical Consultants and Data Engineers having healthy experience into Big Data technologies,IOT/Cloud/AWS and Python/AI+Machine Learning. The Dynamic force has qualified engineers having expertise in Lagi

$143 USD dalam 3 hari
(3 Ulasan)
2.0
Sachin4373

Have a experience in handling CLID issues in production environment Relevant Skills and Experience Asterisk Engineer Proposed Milestones $88 USD - Pass CLID to softphone.

$88 USD dalam 2 hari
(0 Ulasan)
0.0